An enclosure of volume 3 litre contains 16 gms of oxygen, 7 gms of nitrogen and 11 gms of carbon di-oxide at 27 $^{0}$ C . The pressure exerted by the mixture is approximately

1 atmosphere

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 atmosphere

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9 atmosphere

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8.3 atmosphere

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 8.3 atmosphere
Moles of oxygen= $\frac{m}{M} = \frac{16}{32} = 1 / 2$
Moles of nitrogen= $7 / 28 = 1 / 4$
Moles of carbon-dioxide= $11 / 44 = 1 / 4$
Therefore total moles of gas=1
$P V = n R T$
$⟹ P = \frac{n R T}{V} = \frac{1 \times 8.314 \times 300}{3 \times 10^{- 3}} \approx 8.3 a t m$

Suggest Corrections

Similar questions

Q. An enclosure of volume 3 litre contains 16 gm of oxygen, 7 gm of nitrogen and 11 gm of carbon-di-oxide at

27^{\circ}

C. Find the pressure exerted by the mixture

Q. An enclosure of volume 3 litre contains 16g of oxygen, 7g of nitrogen and 11g of carbondioxide at 27

^{o}

C. The pressure exerted by the mixture is approximately

A vessel of volume 4 litres contains a mixture of 8gms of O $_{2}$ , 14 gms of N $_{2}$ and 22 gms of CO $_{2}$ at 27 $^{0}$ C. The pressure exerted by the mixture is

Q. A gas mixture contains 4

g m s

of hydrogen and 42

g m s

of nitrogen. The fraction of the total pressure exerted by nitrogen is:

Q. One half mole each of nitrogen, oxygen and carbon dioxide are mixed in enclosure of volume

5

litres and temperature

27^{o}

C. The pressure exerted by mixture is

(R = 8.31 J m o l^{- 1} K^{- 1})

Join BYJU'S Learning Program

An enclosure of volume 3 litre contains 16 gms of oxygen, 7 gms of nitrogen and 11 gms of carbon di-oxide at 270C . The pressure exerted by the mixture is approximately

The correct option is D 8.3 atmosphereMoles of oxygen=mM=1632=1/2Moles of nitrogen=7/28=1/4Moles of carbon-dioxide=11/44=1/4Therefore total moles of gas=1PV=nRT⟹P=nRTV=1×8.314×3003×10−3≈8.3atm

An enclosure of volume 3 litre contains 16 gms of oxygen, 7 gms of nitrogen and 11 gms of carbon di-oxide at 27 $^{0}$ C . The pressure exerted by the mixture is approximately