The correct option is D ΔH=+ve ;ΔS=+ve
ΔG=ΔH−TΔS
Since the reaction is endothermic, ΔH = +ve
As the temperature increases from freezing to boiling, the reaction becomes spontaneous, i.e. ΔG decreases, i.e. TΔS becomes more negative. This is possible only if ΔS is positive.