Question

An energy of 24.6 eV is required to remove one of the electrons from a ground state neutral helium atom. The energy (in eV) required to remove both the electrons from ground state of a neutral helium atom is

• A. 79.0
• B. 51.8
• C. 49.2
• D. 38.2

Answer 1

The correct option is A 79.0

After the removal of first electron remaining atom will be hydrogen like atom. So energy required to remove second electron from the atom $E=13.6\times \frac{2^2}{1}=54.4eV$
$\therefore$ Total energy required = 24.6 + 54.4 = 79 eV