An engine can pull $500$ metric ton load up and inclined plane rising $1$ in $100$ with a speed of $10 m s^{- 1}$ . The frictional force offered by the plane is $2000$ N. What is the power of the engine?
Given: $1$ metric ton $= 10^{3}$ kg and $g = 9.8 m$ $s^{- 2}$ .

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Solution

Net upward force in pulling the engine up,
$f = m g sin θ$ +frictional force.
Mass of body $= 500 \times 100 = 50000 k g$
$sin θ = 1 / 100$
Frictional force $= 2000 N$
$f = 51000 N$
Power =force $\times$ velocity
$= 51000 \times 10 = 510000$
$= 5.1 \times 10^{5} w a t t = 510 K W$

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An engine can pull 500 metric ton load up and inclined plane rising 1 in 100 with a speed of 10ms−1. The frictional force offered by the plane is 2000N. What is the power of the engine?Given: 1 metric ton =103kg and g=9.8m s−2.

Net upward force in pulling the engine up,f=mgsinθ+frictional force.Mass of body =500×100=50000kgsinθ=1/100Frictional force =2000Nf=51000NPower =force × velocity=51000×10=510000=5.1×105watt=510KW

An engine can pull $500$ metric ton load up and inclined plane rising $1$ in $100$ with a speed of $10 m s^{- 1}$ . The frictional force offered by the plane is $2000$ N. What is the power of the engine?
Given: $1$ metric ton $= 10^{3}$ kg and $g = 9.8 m$ $s^{- 2}$ .

Net upward force in pulling the engine up,
$f = m g sin θ$ +frictional force.
Mass of body $= 500 \times 100 = 50000 k g$
$sin θ = 1 / 100$
Frictional force $= 2000 N$
$f = 51000 N$
Power =force $\times$ velocity
$= 51000 \times 10 = 510000$
$= 5.1 \times 10^{5} w a t t = 510 K W$