An engine develops $20 kW$ of power. How much time will it take to slowly lift a mass of $100 kg$ to a height of $20 m$ ?

$(g = 10 {m/s}^{2})$

4 s

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5 s

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1 s

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10 s

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Solution

The correct option is C $1 s$
$Power = \frac{work}{time}$
Given, power $P = 20 kW = 20000 W$

$\Rightarrow \frac{m g h}{t} = 20000$

$\Rightarrow \frac{100 \times 10 \times 20}{t} = 20000$

$\Rightarrow t = 1 s$

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