An engine exerts a force F-30 -8 -5 k- - vehicle moves with v -4 -20 - C k- if speed of particle at an instant is maximum- then C -A- 6B- -8C- -2D- -6

The correct option is A 6P=F⃗.V⃗=240 160+5C Speed max implies: P = 0 5C+80=0 C= 16 ...

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Normal Reaction

An engine exe...

Question

An engine exerts a force $\to F = 30^i - 8^j + 5^k$ & vehicle moves with $\to v = 4^i + 20^j + C^k$ , if speed of particle at an instant is maximum, then $C$ =

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Solution

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\to F = (20^i - 3^j + 5^k) N

\to v = (6^i + 20^j - 3^k) m / s .

2 kg

(0, 0)

\to V = 4^i + 4^j m/s

\to F = - 20^j N

x -

y -

_{1} = - 4^i - 5^j + 5^k,_{2} = - 5^i + 8^j + 6^k,_{3} = - 3^i + 4^j - 7^k

_{4} = 12^i - 3^j - 2^k

\to F = (15^i + 60^j - 3^k) N

\to v = (- 4^i + 2^j + 5^k)

2 kg

(4^i + 2^j) {ms}^{- 1}

\to F = (2^i - 8^j) N

(2, 3) m

y = 3 m,

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