An engine of the train moving with uniform acceleration passes an electric pole with velocity u and the last compartment with velocityv. the middle point of the train passes past the same pole with the velocity of
A
u+v2
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B
√u2+v22
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C
√u+v2
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D
√v2−u22
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Solution
The correct option is B√u2+v22 Let the length of the train be 2s.
Apply the equation of motion: v2−u2=2as;
v2−u2=2a(2s);
v2−u2=4as;
=a=v2−u24s......Eq:01
According to question, for half train, the length is 2s2=s and
velocity is V;
Again apply the equation of motion: v2−u2=2as;
V2−u2=2a(s)
Put the value of acceleration (a) from Eq:01 in above equation;