Question

An engine pulls a train 1 Km over a level track with constant speed. Calculate the work done by the train. Given that the frictional resistance $5\times {10}^{5}N$.

Answer 1

Given that,

Distance $d=1km=1000m$

Force $F=5\times {10}^{5}N$

$\because$ Train is moving with constant speed then,

Force applied by the engine = Friction force

Now, the work done by train = work done by friction force

$W=F\cdot s$

$W=5\times {10}^5\times 1000$

$W=5\times {10}^{8}J$

Hence, the work done by the train $5\times {10}^{8}J$