An engine pumps up 100 kg water through a height of 10 m in 5s. Given that the efficiency of the engine is 60%. If g = 10 m/s², then the power of the engine is

Q. An engine pumps up

100 k g

of water through a height of

10 m

5 s

. Given that the efficiency of the engine is

60 %

, what is the power of the engine? Take

g = 10 m s^{- 2}

Q. A engine pumps up 100 kg of water trough a height of 10 m in 5s. Given that efficiency of engine is 60%. If

g = 10 m s^{- 2}

, the power of this engine is

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An engine pumps up 1000 kg of coal from a mine 100 m deep in 0.5 s. The pump is running with diesel and efficiency of diesel engine is 25%. then its power consumption will be (g=10m/s2).

The correct option is B 8000 kWP=mght=1000g1000.5=2000kW0.25×power consumption=2000kW Power consumption=8000kW

An engine pumps up $1000 k g$ of coal from a mine $100 m$ deep in $0.5 s$ . The pump is running with diesel and efficiency of diesel engine is $25 %$ . then its power consumption will be $(g = 10 m / s^{2})$ .

The correct option is B $8000 k W$
$P = \frac{m g h}{t} = \frac{1000 g 100}{0.5} = 2000 k W$
$0.25 \times$ power consumption= $2000 k W$
Power consumption= $8000 k W$