An engine uses 720 KJ of energy in 2 hours. Calculate total electricity charges(in rupees) in two hours at a rate of 2.5 rupees per kWh?
0.5

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Solution

The correct option is A 0.5
1 kWh is defined as the electrical energy equivalent to the power consumption for 1 hour.
So, 1 kWh = 1000 W $\times$ 3600 s = 3600000 J = 3600 KJ. (As 1 hour = 3600 seconds)
Given, the cost of 1kWh( = 3600KJ) is 2.5 rupees.
So, the cost of 1 KJ is $\frac{2.5}{3600}$ rupees.
$⟹$ Total cost of the consumed electricity = $\frac{2.5 \times 720}{3600}$ = 0.5 rupees.

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An engine uses 720 KJ of energy in 2 hours. Calculate total electricity charges(in rupees) in two hours at a rate of 2.5 rupees per kWh?0.5

An engine uses 720 KJ of energy in 2 hours. Calculate total electricity charges(in rupees) in two hours at a rate of 2.5 rupees per kWh?
0.5