Question

An engineer is designing the runway for an airport of the planes that will use the airport, the lowest acceleration rate is likely to be $3m/s^2$. The takeoff speed for this plane will be $65m/s$. Assuming this minimum acceleration, what is the minimum allowed length for the runway? (in m)

• A. $704$
  
• B. $70$
  
• C. $705$
  
• D. $707$
  

Answer 1

The correct option is A $704$

Given, initial velocity, $u=0m/s$ and final velocity $v=65m/s$

Acceleration $a=3m/s^2$

If $d$ be the allowed length for the runway.

Using formula $v^2-u^2=2aS$

$(65{)}^2-0^2=2(3)d$

$⟹$ $d={65}^2/6=704.16\sim 704m$