Question

An enzyme contains 5.6% Fe. Calculate number of Fe atoms present in 1gm of this enzyme.

Answer 1

• Given the weight of enzyme $=1gm$
• $\therefore$ Weight of Fe atoms

  $=5.6\%of1gm$

  $=\frac{56}{100}\times 1$

  $0.056gmofFeatoms$

• We know, that 1 mole of Fe atoms weighs 55 gm. thus, the number of Fe atoms present in 1 gm of enzyme

  $=0.056\times \frac{1}{55}\times \frac{6.022\times {10}^{23}}{1}$

  $=6.131\times {10}^{20}Featoms$