The correct option is A 1
According to the question, the restriction sequence for the enzyme is a 8 base pair long sequence. If suppose, an arbitrary DNA sequence of 8 base pair as XXXXXXXX, where “X” can be any of four nucleotides (A/T/G/C); there are 4 possibilities for one “X” and the total sequence is 8 base pairs. For all 8 bases; the probability of having the given sequence is (4 x 4 x 4 x 4 x 4 x 4 x 4 x 4 = 65,536 base pairs) which means that the given restriction site occur every 65,536 base pairs. For a DNA segment of 70 kb; the possibility of having the given sequence = 70000/65,536 = around 1. The correct answer is A.