An equal-biconvex lens (μ=1.5) of focal length 20cm is cut into two parts and placed in contact as shown in the figure. A liquid of refractive index 1.3 is filled between the two parts of lens. The equivalent focal length of the combination is
A
203cm
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B
50cm
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C
803cm
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D
30cm
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Solution
The correct option is B50cm Hint: Consider three lenses are in contact
Sol: R=20cm
and therefore; 1f2=(1.3−1)(−220)=−3100
and therefore; 1fe=120−3100⇒fe=50cm