An equation equivalent to the quadratic equation $x^{2} - 6 x + 5 = 0$ is

6 x^{2} - 5 x + 1 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{2} - 5 x + 6 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 x^{2} - 6 x + 1 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

| x - 3 | = 2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $| x - 3 | = 2$
Given equation is: $x^{2} - 6 x + 5 = 0$
$x^{2} - 5 x - x + 5 = 0$
$x (x - 5) - 1 (x - 5) = 0$
$(x - 1) (x - 5) = 0$
$x = 1$ and $x = 5$
Now
$x = 1$
$x - 3 = - 2$
$x - 3 = - 2$ ...(i) and
$x = 5$
$x = 3 + 2$
$x - 3 = 2$ ...(ii)
Combining i and ii, we get
$x - 3 = | 2 |$
or
$| x - 3 | = 2$

Suggest Corrections

Similar questions

If $α, β$ are the roots of the equation $2 x^{2} + 5 x + 6 = 0$ , then find the equation whose roots are $\frac{1}{α} a n d \frac{1}{β}$ .

x^{2} - 5 x + 6 = 0

6 x^{2} - 13 x + 6 = 0

\sqrt{6} x^{2} - 5 x + \sqrt{6} = 0

24 x^{2} - 17 x + 3 = 0

x^{2} + 2 x + 4 = 0

x^{2} + x + 1 = 0

x^{2} - 3 \sqrt{3} x - 30 = 0

3 x^{2} - 5 x + 7 = 0

\sqrt{3} x^{2} - 10 x - 8 \sqrt{3} = 0

6 x^{2} - 5 x + 1 = 0

x^{2} - 5 x + 6 = 0

(1) x^{2} + 6 x + 5 = 0

(2) x^{2} - 3 x - 4 = 0

(3) 5 x^{2} + 8 x + 3 = 0

(4) 5 x^{2} - 3 x - 2 = 0

(5) 3 x^{2} + 5 \sqrt{2} x - 2 = 0

(6) x^{2} + 5 x + 3 = 0

(7) 9 x^{2} + 6 x + 4 = 0

(8) 48 m^{2} - 13 m - 1 = 0

Join BYJU'S Learning Program