CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
136
You visited us 136 times! Enjoying our articles? Unlock Full Access!
Question

An equation of the chord of the circle x2+y2=a2 passing through the point (2,3) farthest from the centre is

A
2x+3y=13
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
3xy=3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x2y+4=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
xy+1=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2x+3y=13

Let P(2,3) be the given point

M be the middle point of a chord of the circle x2+y2=a2 through P.
Then the distance of the centre O of the circle from the chord is
OM
and (OM)2=(OP)2(PM)2 ( From figure )
Which is maximum when PM is minimum,

i.e. M coincides with P

i.e. P is the middle point of the chord.

Hence, the equation of the chord is
2x+3ya2=22+32a2

2x+3y=13.

366567_196562_ans_3d1eddd45eaf46f08943a5a4c227d1ea.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon