1
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Question

# An equiconvex air lens (R1=R2=10 cm) is made in glass medium having refractive index (μ=32). Find the refractive index of the material to be filled in, so that the power of the lens changes without change in its magnitude.

A
32
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B
2
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C
1.8
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D
1.2
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Solution

## The correct option is B 2 Given, Refractive index of glass = 32 R1=R2=10 cm As we know that the lens maker formula is given by 1f=(μ2μ1−1)(1R1−1R2) For Case−I 1f=(23−1)(1R−1−R) 1f=(23−1)2R .......(1) For case−II 1−f=(2μ3−1)(1R−1−R) 1−f=(2μ3−1)2R .......(2) From equation (1) and (2) −(23−1)2R=(2μ3−1)2R 13=(2μ3−1) ⇒ μ=2 <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (B) is the correct answer.

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