Question

An equilateral ABC is inscribed in a circle with centre O. Then measure of $\angle BOC$ is

• A. ${30}^o$
• B. ${60}^o$
• C. ${90}^o$
• D. ${120}^o$

Answer 1

The correct option is D

${120}^o$

$\Delta ABC$ is an equilateral triangle inscribed in a circle with centre O.

$\therefore$ Measure of $\angle BOC=2\angle BAC$$=2\times {60}^o={120}^o$