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Question

An equilateral prism deviates a ray through 40° for two angles of incidence differing by 20°. What can be the possible angles of incidence?

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Solution

Angle of deviation, d = 40°
Angle of the prism, A = 60°
Let the two angles of incidence be i1
and (i2= i1+20°).
When the emergent ray (angle of emergence = e) acts as incident ray, the deviation will be same.
i2=e
Now, D = i + e – A
40o=i1+i2A
40o=i1+i1+20o60o
40o=i1+i140o
2i1=80o
i1=40o
i2=i1+20o
=40o+20o
=60o

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