An equilateral trangle is inscribed in the parabola $y^{2} = 8 x$ , with one of its vertices is the vertex of the parabola.Then, the length of the side of that triangle is

24 \sqrt{3}

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16 \sqrt{3}

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8 \sqrt{3}

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4 \sqrt{3}

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Solution

The correct option is B $16 \sqrt{3}$
$(\begin{matrix} \frac{\sqrt{3} x}{2}, \frac{x}{2} \end{matrix})$ lies on $y^{2} = 8 x$
$\Rightarrow s i d e x = 16 \sqrt{3}$

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An equilateral trangle is inscribed in the parabola y2=8x, with one of its vertices is the vertex of the parabola.Then, the length of the side of that triangle is

The correct option is B 16√3(√3x2,x2) lies on y2=8x⇒sidex=16√3

An equilateral trangle is inscribed in the parabola $y^{2} = 8 x$ , with one of its vertices is the vertex of the parabola.Then, the length of the side of that triangle is

The correct option is B $16 \sqrt{3}$
$(\begin{matrix} \frac{\sqrt{3} x}{2}, \frac{x}{2} \end{matrix})$ lies on $y^{2} = 8 x$
$\Rightarrow s i d e x = 16 \sqrt{3}$