An equilateral triangle ABC is inscribed in a circle centered at O and of radius 4 cm, as shown below. OD is a radius such that it is perpendicular to BC and cuts BC at point E. Then the length of OE is

0.5 cm

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1 cm

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2 cm

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3 cm

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Solution

The correct option is C
2 cm

Given, OD is a radius such that it is perpendicular to BC and OD = 4 cm.

We know that a side of an equilateral triangle drawn with vertices on a circle bisects the radius perpendicular to it.

So, the side BC of equilateral triangle ABC bisects the radius OD and hence OE = ED = $\frac{O D}{2}$ = 2 cm.

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