An equilateral triangle ABC is inscribed in a circle with centre O. Then, ∠BOC is equal to:
120°
Given, ΔABC is an equilateral triangle.
If, ∠BAC=60∘
So, ∠BOC=2 ∠BAC=120∘
[The angle subtended by a chord at the centre of a circle is twice the angle subtended by the same chord at any other point on the remaining part of the circle.]