Question

An equilateral triangle has area $Ac{m}^2$. A regular hexagon of maximum area is cut off from the triangle. If the area of the hexagon is $320c{m}^2$, then the area $A$ is

• A. $640c{m}^2$
• B. $480c{m}^2$
• C. $600c{m}^2$
• D. $400c{m}^2$

Answer 1

The correct option is B $480c{m}^2$

$6$ smaller triangles constitue ine hexagon.
$\therefore$ Nine equilateral triangles give the area of bigger triangle.
Now,
$6$ triangles=$320c{m}^2$
$\therefore 9$ triangles=$\frac{320}{6}\times 9$
=$480c{m}^2$