An equilateral triangle has its centroid at origin and one side is x + y = 1. The equations of the others sides are
A
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B
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C
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D
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Solution
The correct option is A Third vertex ‘A’ lies on x – y =0 and in III quadrent Perpendicular distance from (0,0) to x + y =1 is 1√2 \(\therefore AO = \sqrt{2} \Rightarrow A(-1,-1)\) If m is the slope of other side, \(\tan 60^\circ = \left | \frac{m+1}{1-m} \right |\) ⇒m=2±√3