An equilateral triangle inscribed in the circle x 2- y 2-2 g x -2 fy - c -0 then its side isA- 3 -g2-f2-cB- -3g2-f2-cC- -g2-f2-c-3D- 2 -g2-f2-c

The correct option is B r=√(g^2+f^2 c) AD^2=a^2 a^2/4 AD=√(3)/2a r=2/3AD =a/√(3) a=√(3)r =√(3(g^2+f^2 c)) ...

481

You visited us 481 times! Enjoying our articles? Unlock Full Access!

Slope Form a Line

An equilatera...

Question

An equilateral triangle inscribed in the circle $x^{2} + y^{2} + 2 g x + 2 f y + c$ = 0 then its side is

$3\sqrt{g^2+f^2-c}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\sqrt{3(g^2+f^2-c)}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$\frac{\sqrt{g^2+f^2-c}}{\sqrt{3}}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$2\sqrt{g^2+f^2-c}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

x^{2} + y^{2} + 2 g x + 2 f y + c = 0

x^{2} + y^{2} + 2 g x + 2 f y + c = 0

(c > 0)

\frac{π}{2},

x^{2} + y^{2} + 2 g x + 2 f y + c = 0

g^{2} < c < f^{2}

x^{2} + y^{2} + 2 g x + 2 f y + c = 0

The centre and radius of the circle $x^{2} + y^{2} + 2 g x + 2 y f + c = 0$ are and respectively.

Join BYJU'S Learning Program