an equilateral triangle is formed by three exactly same uniform rods each of length 0.25m and mass 5kg . Find the moment of inertia about an axis passing through one corner

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$M o m e n t o f i n e r t i a i s M o m e n t o f i n e r t i a o f t h e r o d s w h i c h a r e t o u c h i n g t h e t h e a x i s a r e e a c h e q u a l t o t h e m o m e n t o f i n e r t i a a b o u t t h e a x i s p a s \sin g t h r o u g h t h e e n d o f t h e r o d I = \frac{m l^{3}}{3} m o m e n t o f i n e r t i a o f t h e t h i r d r o d f r o m t h e p a r a l l e l a x i s t h e o r e m I = I_{c m} + m r^{2} I = I_{c m} + m r^{2} r : p e r p e n d i c u l a r d i s \tan c e o f t h e o p p o s i t e s i d e o f t h e r o d f r o m t h e a x i s o r f r o m t h e c o r n e r . F r o m g e o m e t r y o f t r i a n g l e r = \frac{\sqrt{3} l}{2} I = \frac{m l^{3}}{12} + m (\frac{\sqrt{3} l}{2})^{2} I = \frac{m l^{3}}{3} + \frac{m l^{3}}{3} + [\frac{m l^{2}}{12} + m (\frac{\sqrt{3} l}{2})^{2}] I = \frac{2 m l^{3}}{3} + [\frac{m l^{2}}{12} + m (\frac{\sqrt{3} l}{2})^{2}] I = \frac{2 m l^{3}}{3} + [\frac{m l^{2}}{12} + \frac{3 m l^{2}}{4}] I = \frac{2 m l^{3}}{3} + [\frac{m l^{2}}{12} + \frac{3 m l^{2}}{4}] = \frac{3}{2} m l^{2} I = \frac{3}{2} \times 5 \times 0 . 25^{2} I = \frac{3}{2} \times 5 \times 0 . 25^{2} = 0.468 k g m^{2} R e g a r d s$

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\begin{matrix} Three identical uniform rods each of length 1 m and mass 2 k g are arranged to form an equilateral triangle. What is the moment of inertia of the system about an to axis passing through one corner and perpendicular to the plane of the triangle: \end{matrix}

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