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Byju's Answer

Standard XIII

Physics

Torque

An equilatera...

Question

An equilateral triangular loop of side l carries a current I. It is placed in a magnetic field B such that the plane of the loop is in the direction of B. The torque on the loop is

Zero

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IBl

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\frac{\sqrt{3}}{2} I l^{2} B^{2}

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\frac{\sqrt{3}}{4} I B l^{2}

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Solution

The correct option is D $\frac{\sqrt{3}}{4} I B l^{2}$
Since $θ = 90^{\circ}$
Hence $τ = N I A B = 1 \times I \times (\frac{\sqrt{3}}{4} l^{2}) B$
$= \frac{\sqrt{3}}{4} l^{2} B I$

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An equilateral triangular loop of side l carries a current I. It is placed in a magnetic field B such that the plane of the loop is in the direction of B. The torque on the loop is

The correct option is D √34I B l2Since θ=90∘ Hence τ=NIAB=1×I×(√34l2)B =√34l2BI

The correct option is D $\frac{\sqrt{3}}{4} I B l^{2}$
Since $θ = 90^{\circ}$
Hence $τ = N I A B = 1 \times I \times (\frac{\sqrt{3}}{4} l^{2}) B$
$= \frac{\sqrt{3}}{4} l^{2} B I$