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Byju's Answer
Standard VII
Chemistry
Chemical Formulae
An equilibriu...
Question
An equilibrium mixture for the reaction 2 H2S = 2H2+ S2 has 1 mole of hydrogen sulphide,0.2 mole of H2 and 0.8 mole of S2 in 2 Litre vessel.The value of Kc is A 0.004 B 0.080 C 0.016 D 0.160
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Q.
An equilibrium mixture for the reaction:
2
H
2
S
(
g
)
⇔
2
H
2
(
g
)
+
S
2
(
g
)
had 1 mole of
H
2
S
, 0.2 mole of
H
2
and 0.8 mole of
S
2
in 2 L flask. The
value of
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c
in
m
o
l
.
l
i
t
−
1
is;
Q.
An equilibrium mixture of the reaction
2
H
2
S
(
g
)
⇌
2
H
2
(
g
)
+
S
2
(
g
)
had 0.5 mole
H
2
S
,
0.10
m
o
l
e
H
2
and 0.4 mole
S
2
in one litre vessel. The value of equilibrium constant (K) in mole
l
i
t
r
e
−
1
is
Q.
An equilibrium mixture for the reaction
H
2
S
(
g
)
⇌
H
2
(
g
)
+
S
2
(
g
)
had 1 mol of hydrogen sulphide, 0.2 mol of
H
2
and 0.8 mol of
S
2
in a 2 L vessel. The value of
K
c
in M is
Q.
An equilibrium mixture for the reaction
2
H
2
S
(
g
)
⇌
2
H
2
(
g
)
+
S
2
(
g
)
has
1
m
o
l
e
of
H
2
S
,
0.2
m
o
l
e
of
H
2
and
0.8
m
o
l
e
of
S
2
in a
2
litre flask. The value of
K
c
in mol
L
−
1
is
Q.
In the reaction,
H
2
+
I
2
⇌
2
H
L
. In a
2
litre flask
0.4
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H
2
&
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are taken. AT equilibrium
0.5
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K
c
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