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Question

An equilibrium mixture in a vessel of capacity 100 litre contain 1molN2,2molO2 and 3molNO.No.ofmolesofO2 to be added so that at new equilibrium the conc. of NO is found to be 0.04 mol/lit :

A
(101/18)
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B
(101/9)
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C
(202/9)
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D
None of these
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Solution

The correct option is A (101/18)
N2+O22NO
0.01M 0.02M 0.03M

KC=0.0320.01×0.02=4.5

Let a moles of O2 be added (25:5 O2 9a
N2+O22NO
0.01-x 0.02+a-x 0.03 + 2x
0.03+2x=0.04
x=0.005

i.e., 4.5=(0.04)2(0.015+a)(0.005)

Moles of O2
added=a×100=10118

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