An equilibrium mixture of PCl5- PCl3 and Cl2 at a certain temperature contains 0-5 - 10-3 M PCL5 1-5 - 10-2 M PCL3 and 3- 10-2 M Cl2 -Calculate the equilibrium constant Kc for the reaction PCL5 g - PCl3 g- Cl2 g -

PCl_5( g ) ⇌ PCl_3( g ) + Cl_2( g ) [ K_ C =[ PC l_ 3 ] [ C l_ 2 ] #160; /[ PC l_ 5 ] #160; =( 3× 10 ^ 2 ) ( 1.5× 10 ^ 2 ) #160; / 0.5× ...

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Byju's Answer

Standard XII

Chemistry

Characteristics of Equilibrium Constant

An equilibriu...

Question

An equilibrium mixture of $P C l_{5}, P C l_{3}$ and $C l_{2}$ at a certain temperature contains $0.5 \times 10^{- 3} M P C L_{5}$ $1.5 \times 10^{- 2} M P C L_{3}$ and $3 \times 10^{- 2} M C l_{2}$ .Calculate the equilibrium constant $K_{c}$ for the reaction $P C L_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)$ .

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Solution

$P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)$
$\begin{matrix} K_{C} = \frac{[P C l_{3}] [C l_{2}]}{[P C l_{5}]} = \frac{(3 \times 10^{- 2}) (1.5 \times 10^{- 2})}{0.5 \times 10^{- 3}} K_{C} = 0.9 \end{matrix}$

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Similar questions

Q. An equilibrium mixture of

P {C l}_{5}, P {C l}_{3}

and

{C l}_{2}

at a certain temperature contians

0.5 \times 10^{- 3} M

P {C l}_{3}

1.5 \times 10^{- 2}

P {C l}_{3}

and

3 \times 10^{- 2} M

{C l}_{2}

. Calculate the equilibrium constant

K_{c}

for the reaction

P {C l}_{5} (g) ⇌ P {C l}_{3} (g) + {C l}_{2} (g)

Q. At a certain temperature, the reaction

P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)

has an equilibrium constant

K_{c} = 5.8 \times 10^{- 2}

. Calculate the equilibrium concentrations of

P C l_{5}, P C l_{3}

and

C l_{2}

if only

P C l_{5}

is present initially at a concentration of

0.160

Q. A quantity of

P C l_{5}

was heated in a 10 litre vessel as

250^{o} C; P C l_{5 (g)} ⇌ P C l_{3 (g)} + C l_{2 (g)}

. At equilibrium the vessel contains 0.1 mole of

P C l_{5}

. 0.20 mole of

P C l_{3}

and 0.2 mole of

C l_{2}

. The equilibrium constant of the reaction is:

A sample of pure $P C l_{5}$ was introduced into an evacuated vessel at 473 K. After equilibrium was attained, concentration of PCl_5 was found to be $0.5 \times 10^{- 1} m o l L^{- 1} . I f v a l u e o f K_{c} i s 8.3 \times 10^{- 3}$ , what are the concentrations of $P C l_{3}$ and $C l_{2}$ at equilibrium?\\
$P C l_{5} (g) \leftrightarrow P C l_{3} (g) + C l_{2} (g)$

Q. At a given temperature, the equilibrium constant for the reaction

P C l_{5} (g) ⇋ P C l_{3} (g) + C l_{2} (g)

2.4 \times 10^{- 3}

. At the same temperature, the equilibrium constant for the reaction

P C l_{3} (g) + C l_{2} (g) ⇋ P C l_{5} (g)

is:

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An equilibrium mixture of PCl5,PCl3 and Cl2 at a certain temperature contains 0.5×10−3MPCL5 1.5×10−2MPCL3 and 3×10−2MCl2 .Calculate the equilibrium constant Kc for the reaction PCL5(g)⇌PCl3(g)+Cl2(g) .

PCl5(g)⇌PCl3(g)+Cl2(g)KC=[PCl3][Cl2][PCl5]=(3×10−2)(1.5×10−2)0.5×10−3KC=0.9

$P C l_{5} (g) ⇌ P C l_{3} (g) + C l_{2} (g)$
$\begin{matrix} K_{C} = \frac{[P C l_{3}] [C l_{2}]}{[P C l_{5}]} = \frac{(3 \times 10^{- 2}) (1.5 \times 10^{- 2})}{0.5 \times 10^{- 3}} K_{C} = 0.9 \end{matrix}$