An equilibrium triangle ABC has its centroid at the origin and the base BC lies along the line x+y=1. Then the area of ΔABC is
The triangle ABC has medians AD, BE, CF . AD lies along the line y = x + 3, BE lies along the line y = 2x + 4, AB has length 60 and angle C = 90°, then the area of triangle ABC is (A) 400 (B) 200 (C) 100 (D) none of these