An event A has the outcomes w1 - w2 - w3 and w4 with probabilities 1-12-1-12-1-6 and 1-3-If theprobability of event A is PA-find 24 PA-

Probability of an event is the sum of probabilities of outcomes. = 1/12 + 1/12 + 1/6 + 1/3 =2/3 ⇒ Answer =2/3×24=16 nbsp; nbsp; nbsp; nbsp; n ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Axiomatic Approach

An event A ha...

Question

An event A has the outcomes $w_{1}, w_{2}, w_{3}$ and $w_{4}$ with probabilities $\frac{1}{12}, \frac{1}{12}, \frac{1}{6}$ and $\frac{1}{3}$ .If the

probability of event A is P(A),find 24 P(A).
___

Open in App

Solution

Suggest Corrections

Similar questions

w_{1}, w_{2}, w_{3}

w_{4}

\frac{1}{12}, \frac{1}{12}, \frac{1}{6} and \frac{1}{3}

An event A has the outcomes $w_{1}, w_{2}, w_{3}, a n d w_{4}$ with probabilities $\frac{1}{12}, \frac{1}{12}, \frac{1}{6} a n d \frac{1}{3}$ .If the

probability of event A is P(A),find 24 P(A).

\frac{1}{12}

\frac{1}{6}

A = (w_{1}, w_{2} \dots . . w_{n})

w_{1}, w_{2} \dots . . w_{n}

P (A) = P (w_{1}) + P (w_{2}) \dots . . P (w_{n})

A

C

A, B

C

P (A) = \frac{1}{5}, P (B) = \frac{1}{6},

P (A \cap C) = \frac{1}{20}, P (B \cup C) = \frac{3}{8}

Join BYJU'S Learning Program