An event A has the outcomes w 1- w 2- w 3- and w 4 with probabilities 1-12- 1-12- 1-6 and 1-3-If the probability of event A is P A - find 24 P A -

Probability of an event is the sum of probabilities of outcomes. = 1/12 + 1/12 + 1/6 + 1/3 =2/3 ⇒ Answer =2/3 × 24 ...

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An event A ha...

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An event A has the outcomes $w_{1}, w_{2}, w_{3}, a n d w_{4}$ with probabilities $\frac{1}{12}, \frac{1}{12}, \frac{1}{6} a n d \frac{1}{3}$ .If the

probability of event A is P(A),find 24 P(A).

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An event A has the outcomes $w_{1}, w_{2}, w_{3}$ and $w_{4}$ with probabilities $\frac{1}{12}, \frac{1}{12}, \frac{1}{6}$ and $\frac{1}{3}$ .If the

probability of event A is P(A),find 24 P(A).

w_{1}, w_{2}, w_{3}

w_{4}

\frac{1}{12}, \frac{1}{12}, \frac{1}{6} and \frac{1}{3}

\frac{1}{12}

\frac{1}{6}

Which of the following cannot be valid assignment of probability for elementary events or outcomes of sample space

$S = {w_{1}, w_{2}, w_{3}, w_{4}, w_{5}, w_{6}, w_{7}}$ :
Elementary events :

(i) $\begin{matrix} w_{1} & w_{2} & w_{3} & w_{4} & w_{5} & w_{6} & w_{7} 0.1 & 0.01 & 0.05 & 0.03 & 0.01 & 0.2 & 0.6 \end{matrix}$

(ii) $\begin{matrix} \frac{1}{7} & \frac{1}{7} & \frac{1}{7} & \frac{1}{7} & \frac{1}{7} & \frac{1}{7} & \frac{1}{7} \end{matrix}$

(iii) $\begin{matrix} 0.7 & 0.6 & 0.5 & 0.4 & 0.3 & 0.2 & 0.1 \end{matrix}$

(iv) $\begin{matrix} \frac{1}{14} & \frac{1}{14} & \frac{1}{14} & \frac{1}{14} & \frac{1}{14} & \frac{1}{14} & \frac{1}{14} \end{matrix}$

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