An event A has the outcomes w1- w2- w3 and w4 with probabilities 1-12-1-12- 1-6 and 1-3- If the probability of event A is PA- then 24 PA -

Probability of an event is the sum of probabilities of outcomes. ⇒ P(A)=1/12+1/12+1/6+1/3 =2/3 ⇒Answer =2/3× 24 =16 nbsp; ...

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An event A has the outcomes $w_{1}, w_{2}, w_{3}$ and $w_{4}$ with probabilities $\frac{1}{12}, \frac{1}{12}, \frac{1}{6} and \frac{1}{3}$ . If the probability of event A is P(A), then 24 P(A) = ___

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\frac{1}{12}

\frac{1}{6}

If P(A) denotes the probability of an event A, then
(a) P(A) < 0
(b) P(A) > 1
(c) $0 \leq P (A) \leq 1$
(d) $- 1 \leq P (A) \leq 1$

A = (w_{1}, w_{2} \dots . . w_{n})

w_{1}, w_{2} \dots . . w_{n}

P (A) = P (w_{1}) + P (w_{2}) \dots . . P (w_{n})

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