An examination paper containing 12 questions consists of two parts, A and B. Part A contains 7 questions and part B contains 5 questions. A candidate is required to attempt 8 questions, selecting at least 3 from each part. In how many ways can the candidate select the questions?
Clearly, the candidate may select the questions as under:
(i) (3 out of 7 from A) and (5 out of 5 from B) or
(ii) (4 out of 7 from A) and (4 out of 5 from B) or
(iii) (5 out of 7 from A) and (3 out of 5 from B).
The number of ways of these selections are :
Case I 7C3×5C5=35×1=35.
Case II 7C4×5C4=35×5=175.
Case III 7C5×5C3=21×10=210.
Hence, the required number of ways = (35+175+210)=420.