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B
AgNO3+HCl=AgCl+HNO3
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C
2Na+2H2O=2NaOH+H2
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D
KNO3+NaCl=KCl+NaNO3
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Solution
The correct options are APb(NO3)2+2NaI→PbI2+2NaNO3 DKNO3+NaCl=KCl+NaNO3
In reaction B, due to the formation of stable precipitate AgCl, the reaction is stabilised and is irreversible.
In reaction C, H2 gas is liberated which is no more present in the reacting system, as a result the reaction does not go in the reverse direction and it is irreversible.
In reaction A, the products PbI2 and 2NaNO3 react readily to give the reactants again as PbI2 is highly unstable. As a result the reaction is reversible.
In reaction D, K and Na have close reactivities, therefore, they displace each other readily both on the reactant as well as on the product side. Thus, making the reaction reversible.