An excess of AgNO3 is added to 100mL of a 0.01M solution of dichlorotetraaquachromium(III) chloride. The number of moles of AgCl precipitated would be ?
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Solution
No. of moles of complex = M (moles/litre) ×V (litre) =0.01 × (100/1000) =0.001
[Cr(H2O)4Cl2]Cl has one ionizable Cl− 10−3 moles of the complex precipitates the same amount of AgCl