wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

An excess of compound 'A' (molecular formula C3H8O) is treated with acidified potassium dichromate to form a product 'B' (molecular formula C3H6O). 'B' forms a shining silver mirror on warming with ammoniacal silver nitrate. 'B' when treated with an aqueous solution of H2NCONHNH2, HCl and sodium acetate, it gives a product 'C'. Identify the structure of 'C'

A
CH3CH2CH=NHNHCONH2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
CH3CH2CH=NCONHNH2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A CH3CH2CH=NHNHCONH2
A is an alcohol which on oxidation gives aldehyde or ketone (B). Because product (B) give silver mirror test so, it must be an aldehyde.


flag
Suggest Corrections
thumbs-up
2
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Nucleophilic Addition Revisited
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon