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Question

An excess of Hg was added to 103M acidified solution of Fe3+ ions. Its was found that only 4.6% of the ions remained as Fe3+ at equilibrium at 25C. Calculate E for 2Hg/Hg2+2 at 25C for
2Hg+2Fe3+Hg2+2+2Fe2+.

A
0.9121 volt
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B
0.9121 volt
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C
0.7912 volt
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D
0.7912 volt
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Solution

The correct option is D 0.7912 volt
2Hg+2Fe+3Hg2+2+2Fe2+
initial concentration of Fe3+=103M
equilibrium concentration ofFe3+=4.6100103M=4.6×105
equilibrium concentration of Fe2+=95.4% of103M=0.954×103
equilibrium concentration of Hg2+2=Half of the eqilibrium concentration of Fe+2
=0.477×103M
Ecell=0.05911log(0.954)2×106×0.477×103(4.6)2×1010
Ecell=0.0406
EHgHg2+=EcellEred
=0.04020.775
=0.81
0.7912volt

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