The correct option is A (A,C)
Let us assume that 1,2,3,4,5 and 6 are the possible outcomes when the die is thrown.
In the question is given that pair of die is thrown, so sample space will be,
S=⎧⎪
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⎪⎨⎪
⎪
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⎪⎩(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)⎫⎪
⎪
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⎪⎬⎪
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A: the sum is greater than 8,
∴A={(3,6),(4,5),(5,4),(6,3),(4,6),(5,5),(6,4),(5,6)(6,5),(6,6),}
B: 2 occurs on either die
B={(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)(1,2),(3,2),(4,2),(5,2),(6,2),}
C: the sum is at least 7 and a multiple of 3.
So the sum can be only 9 or 12
C={(3,6),(4,5),(5,4),(6,3),(6,6)}
Now, we shall check pairs of these events if they are mutually exclusive or not.
(i) A∩B=ϕ
Since there is no common element between the two sets.
Therefore A & B are mutually exclusive.
(ii) B∩C=ϕ
Since there is no common element between
Therefore B and C are mutually exclusive.
(iii) A∩C={(3,6),(4,5),(5,4),(6,3),(6,6),}⇒{(3,6),(4,5),(5,4),(6,3),(6,6),}≠ϕ
Since A and C has common elements.
Therefore A and C are not mutually exclusive.