CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

An explosion blows a rock into three parts. Two parts go off at right angles to each other. These two are 1 kg first part moving with a velocity of 12 m/s and 2 kg second part moving with a velocity of 8 m/s. If the third part flies off with a velocity of 4 m/s, its mass would be

A
5 kg
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
7 kg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3 kg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
17 kg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 5 kg
Draw a diagram of given situation.

Find the mass of third part.
Formula used: p=mv
Given,
m1=1 kg
v1=12 m/sec
m2=2 kg
v2=8 m/sec
m3=m
v3=4 m/sec
Momentum of first part,
p1=m1v1=1×12=12 kg m/sec
Momentum of second part,
p2=m2v2=2×8=16 kg m/sec
Resultant momentum of two parts is,
(1×12)2+(2×8)2=20 kg m/sec
p3=m3v3=20 kg m/sec
Momentum of third part,
20=m×4 m=5 kg
Final Answer: (A)


flag
Suggest Corrections
thumbs-up
7
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon