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Standard XII

Physics

Velocity of COM

An explosion ...

Question

An explosion breaks a rock into three parts in a horizontal plane. Two of them go off at right angles to each other. The first part of mass 1 kg moves with a speed of $12 m s^{- 1}$ and the second part of mass 2 kg moves with $8 m s^{- 1}$ speed. If the third part flies off with $4 m s^{- 1}$ speed, then its mass is

3 kg

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5 kg

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7 kg

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17 kg

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Solution

The correct option is B 5 kg
$_{1} +_{2} +_{3} = \to 0$
$\Rightarrow 1 \times 12^i + 2 \times 8^j +_{3} = 0$
$_{3} = - (12^i + 16^j)$
$P_{3} = \sqrt{12^{2} + 16^{2}} = 20 k g m s^{- 1}$
$m_{3} = \frac{P_{3}}{v_{3}} = 5 k g$

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An explosion breaks a rock into three parts in a horizontal plane. Two of them go off at right angles to each other. The first part of mass 1 kg moves with a speed of 12ms−1 and the second part of mass 2 kg moves with 8ms−1 speed. If the third part flies off with 4ms−1 speed, then its mass is

The correct option is B 5 kg→P1+→P2+→P3=→0⇒1×12^i+2×8^j+→P3=0→P3=−(12^i+16^j)P3=√122+162=20kgms−1m3=P3v3=5kg

The correct option is B 5 kg
$_{1} +_{2} +_{3} = \to 0$
$\Rightarrow 1 \times 12^i + 2 \times 8^j +_{3} = 0$
$_{3} = - (12^i + 16^j)$
$P_{3} = \sqrt{12^{2} + 16^{2}} = 20 k g m s^{- 1}$
$m_{3} = \frac{P_{3}}{v_{3}} = 5 k g$