An Express train $18 m$ long is running at the rate of $45 k m$ per hour. In how much time will it take to cross a platform to $180 m$ ?

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Solution

Time = Distance / Speed

Distance $= 180 + 18 = 198 m$

Speed $= 45 k m / h r = 45 \times \frac{1000}{3600} = \frac{25}{2} m / s$

$T i m e = 198 \times \frac{2}{25}$

$T i m e = 15.84$ sec

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