Question

An express train is moving with a velocity $V_1$ Its driver finds another train is moving on the same track in the same direction with velocity $v_2$ s. To escape collision. driver applies retardation a on the train. The minimum time of escaping collision will be

• A. $t=\frac{v_1-v_2}{a}$
• B. $t=\frac{v_1^2-v_2^2}{2}$
• C. None
• D. Both

Answer 1

The correct option is A $t=\frac{v_1-v_2}{a}$

As the trains moving in the same direction so the initial relative speed

$(V_1-V_2)$ and by applying retardation final relative speed become zero.

From

$\begin{array}{c}V=u-at\\ O=\left(V_1-V_2\right)-at\\ t=\frac{V_1-V_2}{a}\end{array}$