An express train takes 30 min less for a journey of 440 km, if its usual speed is increased by 8 km/hr. Find its usual speed(in km/hr).
A
80
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B
45
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C
65
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D
8
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Solution
The correct option is A80 Let the speed of the car be s and time be t Then, st=440⟹s=440t and (s+8)(t−12)=440 (440t+8)(2t−1)=880 (8t+440)(2t−1)=880t 16t2−8t+880t−440=880t 16t2−8t−440=0 2t2−t−55=0 2t2−11t+10t−55=0 (2t−11)(t+5)=0 t=5.5,−5 Hence time is 5.5 hr Speed =4405.5=80km/hr