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Question

An expression, which when divided by (x+1) gives (x2x+1) as quotient and 3 as remainder is equal to:

A
x32
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B
x31
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C
x3+2
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D
(x3+4)
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Solution

The correct option is D (x3+4)
Dividend=Divisor × Quotient + Remainder
(x+1)×(x2x+1)+3
x(x2x+1)+(x2x+1)+3
(x3x2+x+x2x+1+3)
(x3+4)

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