Question

An exterior angle of a triangle is ${105}^0$ and its two interior opposite angles are equal. Each of these equal angles is

• A. $37\frac{1^0}{2}$
• B. $52\frac{1^0}{2}$
• C. $72\frac{1^0}{2}$
• D. ${75}^0$

Answer 1

Answer: (B)

$52\frac{1^0}{2}$

Given: Exterior angle = ${105}^{\circ }$
Let the two Interior angles be $x$.
Sum of Interior opposite angles = Exterior angle
$x+x=105$
$2x=105$
$x=52{\frac{1}{2}}^{\circ }$