An exterior angle of a triangle is 110° and one of its interior opposite angles is 45°. The other interior opposite angle is
(a) 45°
(b) 65°
(c) 25°
(d) 135°
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Solution

Let the required angle be $x °$ .
We know that an exterior angle of a triangle is equal to the sum of the opposite interior angles.
Then,
$110 ° = 45 ° + x ° \Rightarrow x ° = 65 °$
Therefore, the other interior opposite angle is 65^o

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Question 26

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b) $65^{\circ}$
c) $50^{\circ}$
d) $60^{\circ}$

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