Question

An exterior angle of a triangle is ${110}^{\circ }$ and one of the interior of opposite angles is ${40}^{\circ }$ . Then the other two angles of a triangle are :-

• A. 70°, 70°
• B. 70°, 40°
• C. 110°, 40°
• D. 110°, 75°

Answer 1

The correct option is A

70°, 70°

$\angle A={110}^{\circ }-{40}^{\circ }={70}^{\circ }$ (Exterior angle of a triangle is equal to the sum of 2 opposite interior angles)

$\angle C={180}^{\circ }-{110}^{\circ }={70}^{\circ }$