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Question

An exterior angle of a triangle is 120° and one of the interior opposite angles is 30°. Find the other angles of the triangle.

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Solution

Given: ACD = 120° and ABC = 30°

To Find: A and C

We know that an exterior angle is equal to the sum of its interior opposite angles.

∠A + B = ACD

∠A + 30° = 120°

∠A = 120° 30°

∴∠A = 90°

Also, ACD + ACB = 180° (Linear angles)

120° + ACB = 180°

∠ACB = 180° 120°

∴∠ACB = 60°


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